document.write( "Question 991468: Not sure how to set up this problem?\r
\n" ); document.write( "\n" ); document.write( "Carry has 28.80 less than 2 times as much money as Joe. Joe has 4/5 as much as Carry.
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Algebra.Com's Answer #611332 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "C=amount Carry has; J=amount Joe has
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\n" ); document.write( "C=2J-28.80
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\n" ); document.write( "J=(4/5)C
\n" ); document.write( "(5/4)J=C
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\n" ); document.write( "(5/4)J=2J-28.80
\n" ); document.write( "-0.75J=-28.80
\n" ); document.write( "J=38.40 ANSWER 1: Joe has 38.40
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\n" ); document.write( "C=(5/4)J=(5/4)(38.40)=48.00 ANSWER 2: Carry has 48.00
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\n" ); document.write( "CHECK:
\n" ); document.write( "C=2J-28.80
\n" ); document.write( "48.00=2(38.40)-28.80
\n" ); document.write( "48.00=76.80-28.80
\n" ); document.write( "48.00=48.00\r
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