document.write( "Question 991344: In 3 more years, x will be 6 times as old as y was last year. When y's present age is added to x's present age the total is 68. How old are they? \n" ); document.write( "
Algebra.Com's Answer #611316 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Write an equation for each statement \n" ); document.write( ": \n" ); document.write( " In 3 more years, x will be 6 times as old as y was last year. \n" ); document.write( "x + 3 = 6(y - 1) \n" ); document.write( "x + 3 = 6y - 6 \n" ); document.write( "x - 6y = -6 - 3 \n" ); document.write( "x - 6y = -9 \n" ); document.write( ": \n" ); document.write( "When y's present age is added to x's present age the total is 68. \n" ); document.write( "x + y = 68 \n" ); document.write( "x - 6y = -9; subtract the first equation \n" ); document.write( "----------- \n" ); document.write( "0 + 7y = 77 \n" ); document.write( "y = 77/7 \n" ); document.write( "y = 11 yrs old \n" ); document.write( ": \n" ); document.write( "I'll let you find x, check the solutions in the 1st statement\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " How old are they? \n" ); document.write( " |