document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991427>Question 991427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't figure out the answers to m<T=(3y-36) find the measure of the supplement of <T<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611310 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I can't figure out the answers to m <T=(3y-36) find the measure of the supplement of <T<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "The sum of supplementary angles = 180 degs<BR>\n" );
document.write( "---<BR>\n" );
document.write( "180 - (3y-36) = 216 - 3y degrees<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );