document.write( "Question 991383: 2log2+log150-log6 in base 10 \n" ); document.write( "

Algebra.Com's Answer #611262 by ikleyn(52879) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"2log%2810%2C2%29\"$ + $\"log%2810%2C150%29\"$ - $\"log%2810%2C6%29\"$ = $\"log%2810%2C%28%284%2A150%29%2F6%29%29\"$ = $\"log%2810%2C100%29\"$ = 2.\r
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