document.write( "Question 991363: How many pounds of 80 cent nuts and how many pounds of 50 cent nuts must a dealer use to produce a mixture of 90 pounds to sell at 75 cents per pound? \n" ); document.write( "
Algebra.Com's Answer #611249 by macston(5194)\"\" \"About 
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\n" ); document.write( "E=pounds of 80 cent nuts; F=pounds of 50 cent nuts
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\n" ); document.write( "E+F=90 pounds
\n" ); document.write( "F=90 pounds-E
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\n" ); document.write( "0.50F+0.80E=0.75(90 pounds)
\n" ); document.write( "0.50(90lbs-E)+0.80E=67.5lbs
\n" ); document.write( "45lbs-0.50E+0.80E=67.5lbs
\n" ); document.write( "0.30E=22.5lbs
\n" ); document.write( "E=75lbs
\n" ); document.write( "ANSWER 1: he should use 75 pounds of $0.80 per pound nuts.
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\n" ); document.write( "F=90lbs-E=90lbs-75lbs=15lbs
\n" ); document.write( "ANSWER 2: He should use 15 pounds of $0.50 per pound nuts.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.50F+0.80E=0.75(90 pounds)
\n" ); document.write( "0.50(15lbs)+0.80(75lbs)=67.5lbs
\n" ); document.write( "7.5lbs+60lbs=67.5lbs
\n" ); document.write( "67.5lbs=67.5lbs\r
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