document.write( "Question 991359: Monico invests a total of $24,000 in two accounts paying 11% and 3% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $1,520.00. \n" ); document.write( "
Algebra.Com's Answer #611241 by macston(5194)\"\" \"About 
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\n" ); document.write( "T=amount at 3%; E=amount at 11%
\n" ); document.write( ".
\n" ); document.write( "T+E=$24000
\n" ); document.write( "T=$24000-E
\n" ); document.write( ".
\n" ); document.write( "0.03T+0.11E=$1520
\n" ); document.write( "0.03($24000-E)+0.11E=$1520
\n" ); document.write( "$720-0.03E+0.11E=$1520
\n" ); document.write( "0.08E=$800
\n" ); document.write( "E=$10000
\n" ); document.write( "ANSWER 1: $10000 was invested at 11%.
\n" ); document.write( ".
\n" ); document.write( "T=$24000-E=$24000-$10000=$14000
\n" ); document.write( "ANSWER 2: $14000 was invested at 3%.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.03T+0.11E=$1520
\n" ); document.write( "0.03($14000)+0.11($10000)=$1520
\n" ); document.write( "$420+$1100=$1520
\n" ); document.write( "$1520=$1520\r
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