document.write( "Question 991359: Monico invests a total of $24,000 in two accounts paying 11% and 3% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $1,520.00. \n" ); document.write( "
Algebra.Com's Answer #611241 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "T=amount at 3%; E=amount at 11% \n" ); document.write( ". \n" ); document.write( "T+E=$24000 \n" ); document.write( "T=$24000-E \n" ); document.write( ". \n" ); document.write( "0.03T+0.11E=$1520 \n" ); document.write( "0.03($24000-E)+0.11E=$1520 \n" ); document.write( "$720-0.03E+0.11E=$1520 \n" ); document.write( "0.08E=$800 \n" ); document.write( "E=$10000 \n" ); document.write( "ANSWER 1: $10000 was invested at 11%. \n" ); document.write( ". \n" ); document.write( "T=$24000-E=$24000-$10000=$14000 \n" ); document.write( "ANSWER 2: $14000 was invested at 3%. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "0.03T+0.11E=$1520 \n" ); document.write( "0.03($14000)+0.11($10000)=$1520 \n" ); document.write( "$420+$1100=$1520 \n" ); document.write( "$1520=$1520\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |