document.write( "Question 84833: $\"n%2B%281%2F8%29+-+2-%28n%2F3%29+=+%285%2F6%29\"$ \n" ); document.write( "

Algebra.Com's Answer #61122 by Spec80(9) $\"\"$ $\"About$

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Your question seems to be asking to solve for n in the following:\r
\n" ); document.write( "\n" ); document.write( " $\"n%2B%281%2F8%29+-+2-%28n%2F3%29+=+%285%2F6%29\"$ \r
\n" ); document.write( "\n" ); document.write( "The first step to doing this problem is to combine like terms, therefore we would do $\"n-%28n%2F3%29\"$ and

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\n" ); document.write( "\n" ); document.write( "Then then need to get n by itself on one side and since right now it is $\"%282n%2F3\"$ we want to get that by itself. To do that, we will add $\"%2815%2F8%29\"$ to both sides, so the problem turns out to be:\r
\n" ); document.write( "\n" ); document.write( " $\"+%282n%2F3%29=%2865%2F24%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Then, what we can do is cross multiply to get rid of the fractions, so what that means is we would do 24 x 2x and 3x65 . That makes the problem look like:\r
\n" ); document.write( "\n" ); document.write( " $\"48n=195\"$ \r
\n" ); document.write( "\n" ); document.write( "Finally we divide both sides by 48 to get n by itself, so the problem turns out to be:\r
\n" ); document.write( "\n" ); document.write( " $\"+n+=%28195%2F48%29+\"$
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