document.write( "Question 991101: A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of 40 miles per gallon of gas. During one particular week, the two cars went a combined total of 2000 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week? \n" ); document.write( "
Algebra.Com's Answer #611209 by Theo(13342)\"\" \"About 
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first car gets 15 miles per gallon.
\n" ); document.write( "second car gets 40 miles per gallon.
\n" ); document.write( "both cars went a total of 2000 miles for a total gas consumption of 75 gallons.\r
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\n" ); document.write( "\n" ); document.write( "miles driven by first car is x.
\n" ); document.write( "miles driven by second car is y.\r
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\n" ); document.write( "\n" ); document.write( "gallons consumed by first car is x / 15.
\n" ); document.write( "gallons consumed by second car is y / 40.\r
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\n" ); document.write( "\n" ); document.write( "you have 2 equations.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 2000
\n" ); document.write( "x/15 + y/40 = 75\r
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\n" ); document.write( "\n" ); document.write( "use the first equation to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "you get y = 2000 - x\r
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\n" ); document.write( "\n" ); document.write( "replace y with 2000 - x in the second equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x/15 + (2000 - x) / 40 = 75\r
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\n" ); document.write( "\n" ); document.write( "remove the fractions by multiplying both sides of the equation by 120.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "120 * x / 15 + 120 * (2000 - x) / 40 = 75 * 120\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "8 * x + 3 * (2000 - x) = 9000\r
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\n" ); document.write( "\n" ); document.write( "simplify further by removing parentheses to get:\r
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\n" ); document.write( "\n" ); document.write( "8 * x + 6000 - 3 * x = 9000\r
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\n" ); document.write( "\n" ); document.write( "subtract 6000 from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "8 * x - 3 * x = 3000\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "5 * x = 3000\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 5 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 600\r
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\n" ); document.write( "\n" ); document.write( "since y = 2000 - x, this means that:\r
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\n" ); document.write( "\n" ); document.write( "y = 1400\r
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\n" ); document.write( "\n" ); document.write( "the first car traveled 600 miles.
\n" ); document.write( "the second car traveled 1400 miles.\r
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\n" ); document.write( "\n" ); document.write( "600 + 1400 = 2000
\n" ); document.write( "600 / 15 + 1400 / 40 = 40 + 35 = 75\r
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\n" ); document.write( "\n" ); document.write( "numbers check out.\r
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\n" ); document.write( "\n" ); document.write( "your solution is the the first car traveled 600 miles at 15 miles per gallon and the second car traveled 1400 miles at 40 miles per gallon.\r
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