document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991151>Question 991151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the rectangle is 52m. The length is 6m more than the width. Label set up an equation, and solve for the width and length of the below rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611206 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Make the width = 'x'<BR>\n" );
document.write( "Length = x + 6<BR>\n" );
document.write( "Perimeter = 2 x Width + 2 x Length<BR>\n" );
document.write( "52 = 2(x) + 2(x + 6)<BR>\n" );
document.write( "52 = 2x + 2x + 12<BR>\n" );
document.write( "Collect like terms:<BR>\n" );
document.write( "4x = 52 - 12<BR>\n" );
document.write( "4x = 40<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "Width = 10m<BR>\n" );
document.write( "Length = 16m<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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