document.write( "Question 991298: A parent is 10 times as old as a child. Six years from now, the parent will be 4 times as old as the child will be. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #611176 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "A parent is 10 times as old as a child.
\n" ); document.write( "P = 10C
\n" ); document.write( "Six years from now, the parent will be
\n" ); document.write( "4 times as old as the child will be.
\n" ); document.write( "P + 6 = 4(C + 6)
\n" ); document.write( "Replace P with 10C from top equation.
\n" ); document.write( "10C + 6 = 4(C + 6)
\n" ); document.write( "10C + 6 = 4C + 24
\n" ); document.write( "Collect like terms:
\n" ); document.write( "10C - 4C = 24 - 6
\n" ); document.write( "6C = 18
\n" ); document.write( "C = 3
\n" ); document.write( "Child's age is 3 years
\n" ); document.write( "Parent is 30 years old.
\n" ); document.write( "Hope this helps :-)
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