document.write( "Question 991298: A parent is 10 times as old as a child. Six years from now, the parent will be 4 times as old as the child will be. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #611176 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "A parent is 10 times as old as a child. \n" ); document.write( "P = 10C \n" ); document.write( "Six years from now, the parent will be \n" ); document.write( "4 times as old as the child will be. \n" ); document.write( "P + 6 = 4(C + 6) \n" ); document.write( "Replace P with 10C from top equation. \n" ); document.write( "10C + 6 = 4(C + 6) \n" ); document.write( "10C + 6 = 4C + 24 \n" ); document.write( "Collect like terms: \n" ); document.write( "10C - 4C = 24 - 6 \n" ); document.write( "6C = 18 \n" ); document.write( "C = 3 \n" ); document.write( "Child's age is 3 years \n" ); document.write( "Parent is 30 years old. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |