document.write( "Question 991145: If a complement is 24 more than twice the angle what is the complement \n" ); document.write( "
Algebra.Com's Answer #611167 by Theo(13342)\"\" \"About 
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x is your angle.\r
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\n" ); document.write( "\n" ); document.write( "90 - x is the complement of your angle.\r
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\n" ); document.write( "\n" ); document.write( "the formula for the complement of the angle being 24 more than twice the angle is shown below:\r
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\n" ); document.write( "\n" ); document.write( "90 - x = 2 * x + 24\r
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\n" ); document.write( "\n" ); document.write( "add x to both sides of the equation and subtract 24 from both sides of the equation and you get:\r
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\n" ); document.write( "\n" ); document.write( "90 - 24 = 3 * x\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "66 = 3 * x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 22.\r
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\n" ); document.write( "\n" ); document.write( "your angle is 22.
\n" ); document.write( "the complement is 90 - 22 = 68.\r
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\n" ); document.write( "\n" ); document.write( "the complement is 24 more than twice the angle becomes:
\n" ); document.write( "68 = 2 * 22 + 24 which becomes:
\n" ); document.write( "68 = 44 + 24 which becomes:
\n" ); document.write( "68 = 68 which is true.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the complement of the angle is 68.\r
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