document.write( "Question 991228: The cross section of a flashlight is a parabola. The bulb is at the focus. Suppose the bulb is located 1/4 in from the vertex of the reflector. The width of the cross section through the bulb is 2 in. What is an equation for this parabola? \n" ); document.write( "
Algebra.Com's Answer #611161 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
Try like this:
\n" ); document.write( "\"y=ax%5E2\" for vertex at the origin. A point on the parabola reflector is (1,1/4) using your second part of the description. That is 1 inch on each \"side\" in the cross section at the bulb. That makes the two inch cross section.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F4=a%2A1%5E2\"
\n" ); document.write( "\"a=1%2F4\"
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\n" ); document.write( "\"y=%281%2F4%29x%5E2\", but this may not match the first part of the description for the bulb at the focus, \"1%2F4\" inch from the vertex. Recheck your problem description to be sure.
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