document.write( "Question 991173: sqrt(x+1)+sqrt(x-1)=sqrt(2x+1) \n" ); document.write( "
Algebra.Com's Answer #611139 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\"sqrt%28x%2B1%29\" + \"sqrt%28x-1%29\" = \"sqrt%282x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Square both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+1\" + \"2sqrt%28%28x%2B1%29%2A%28x-1%29%29\" + \"x-1\" = \"2x%2B1\".\r
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\n" ); document.write( "\n" ); document.write( "Simplify:\r
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\n" ); document.write( "\n" ); document.write( "\"2x\" + \"2%2Asqrt%28x%5E2-1%29%29\" = \"2x%2B1\",\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%28x%5E2-1%29\" = \"1\".\r
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\n" ); document.write( "\n" ); document.write( "Square both sides again:\r
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\n" ); document.write( "\n" ); document.write( "\"4%2A%28x%5E2-1%29\" = \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2\" = \"1+%2B+4\" = \"5\",\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2\" = \"5%2F4\",\r
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\n" ); document.write( "\n" ); document.write( "x = +/- \"sqrt%285%29%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "Only positive root suits the original equation  (remember about the term  \"sqrt%28x-1%29\").\r
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\n" ); document.write( "\n" ); document.write( "Answer.  x = \"sqrt%285%29%2F2\".\r
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