document.write( "Question 991079: The width of a rectangle is 1 foot shorter the half the length. The perimeter of the rectangle is 64 feet. What are the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #611025 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make Length = 'x' \n" ); document.write( "Width = x/2 - 1 \n" ); document.write( "Perimeter = 2 x Length + 2 x Width \n" ); document.write( "64 = 2(x) + 2(x/2 - 1) \n" ); document.write( "62 = 2x + x - 2 \n" ); document.write( "collect like terms \n" ); document.write( "3x = 64 + 2 \n" ); document.write( "3x = 66 \n" ); document.write( "x = 22 \n" ); document.write( "Length = 22 feet \n" ); document.write( "Width = 10 feet. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |