document.write( "Question 990990: Jim and Derry run a 1.5 mile loop starting at the same time and place. Jim runs an 8.5 minute mile while Derry runs a 7 minute mile. How far has Jim ran when he is caught by Derry? \n" ); document.write( "
Algebra.Com's Answer #611000 by ankor@dixie-net.com(22740)\"\" \"About 
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Jim and Derry run a 1.5 mile loop starting at the same time and place.
\n" ); document.write( " Jim runs an 8.5 minute mile while Derry runs a 7 minute mile.
\n" ); document.write( " How far has Jim ran when he is caught by Derry?
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\n" ); document.write( "\"1%2F8.5\" mi/min is J's running speed
\n" ); document.write( "\"1%2F7\" mi/min is D's running speed
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\n" ); document.write( "The loop is 1.5 mi long, therefore when D catches up with J, he will have run 1.5 mi further than J
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\n" ); document.write( "let t = time in min for this to happen
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "\"1%2F7\"t = \"1%2F8.5\"t + 1.5
\n" ); document.write( "the least common multiple of the denominators is 59.5 (7*8.5), multiply equation by that and you have
\n" ); document.write( "8.5t = 7t + 59.5(1.5)
\n" ); document.write( "8.5t - 7t = 59.5(1.5)
\n" ); document.write( "1.5t = 59.5(1.5
\n" ); document.write( "Divide both sides by 1.5
\n" ); document.write( "t = 59.5 min for D to catch J
\n" ); document.write( "\"How far has Jim ran when he is caught by Derry?\"
\n" ); document.write( "\"1%2F8.5\" * 59.5 = 7 miles run by Jim when he is caught
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\n" ); document.write( "Interesting that Derry has run 8.5 mi when he catches Jim,1.5 mi further
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