document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991095>Question 991095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter for the figure.  The length of a rectangle is half the width.  The area is 25 square meters.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610997 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter for the figure. The length of a rectangle is half the width. The area is 25 square meters. <BR>\n" );
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document.write( "width:: 2x<BR>\n" );
document.write( "length:: x<BR>\n" );
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document.write( "Area = 2x^2 = 25<BR>\n" );
document.write( "x = 5/sqrt(2) or (5/2)sqrt(2)------ length<BR>\n" );
document.write( "2x = 5sqrt(2)......... width\r<BR>\n" );
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document.write( "Ans: Perimeter = 2[length + width]<BR>\n" );
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document.write( "P = 2[(7/2)sqrt(2)]<BR>\n" );
document.write( "P = 7sqrt(2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );