document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991024>Question 991024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Each coin in the collection of 56 coins is neither silver or gold. The number of silver coins is 8 more than 3 times the number of gold coins. Find the number of gold coins. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610986 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of gold coins plus silver coins equals 56.<BR>\n" );
document.write( "Let's call the number of gold coins x.<BR>\n" );
document.write( "Since the number of silver is 8 more than 3 times the number of gold, we could write it as 8+3X or 3x+8. <BR>\n" );
document.write( "Putting these ways of representing gold and silver coins into the first equation gives:<BR>\n" );
document.write( "gold + silver =56<BR>\n" );
document.write( "x + (3x+8) = 56<BR>\n" );
document.write( "x +3x +8 =56<BR>\n" );
document.write( "4x +8 = 56<BR>\n" );
document.write( "4x+8-8=56-8<BR>\n" );
document.write( "4x+0=48<BR>\n" );
document.write( "4x=48<BR>\n" );
document.write( "4x/4=48/4<BR>\n" );
document.write( "x=12\r<BR>\n" );
document.write( "\n" );
document.write( "So the number of gold coins is 12.<BR>\n" );
document.write( "Silver must be 3(12)+8 = 36+8  = 44.\r<BR>\n" );
document.write( "\n" );
document.write( "Plug these number in to check your work.<BR>\n" );
document.write( "gold+silver=56<BR>\n" );
document.write( "12+44 does equal 56. </SPAN>\n" );
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