document.write( "Question 991063: In 12 years time Ruth will be three times as old as she was 6 years ago . Find Ruth's age now \n" ); document.write( "
Algebra.Com's Answer #610978 by Timnewman(323)\"\" \"About 
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Hi dear,
\n" ); document.write( "Let ruth's age be x
\n" ); document.write( "Six years ago,
\n" ); document.write( "Ruths age=x-6
\n" ); document.write( "In 12years time,
\n" ); document.write( "Ruth's age =x+12
\n" ); document.write( "But,
\n" ); document.write( "x+12=3(x-6)
\n" ); document.write( "x+12=3x-18
\n" ); document.write( "3x-x=12+18
\n" ); document.write( "2x=30
\n" ); document.write( "x=15
\n" ); document.write( "Ruth's age now is 15yrs
\n" ); document.write( "HOPE THIS HELPS?
\n" ); document.write( "::TIMNEWMAN::
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