document.write( "Question 990997: You are biking at a speed of 18 miles per hour. You are 3 miles behind your friend who is biking at a speed of 12 miles per hour. Write and solve an equation to find the amount of time it takes for you to catch up to your friend \n" ); document.write( "

Algebra.Com's Answer #610926 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+d+\"$ = the distance in miles that your friend
\n" ); document.write( "travels until you catch up with your friend
\n" ); document.write( " $\"+d+%2B+3+\"$ = the distance in miles you cover until
\n" ); document.write( "you catch your friend
\n" ); document.write( "Let $\"+t+\"$ = time in hrs it takes to catch your friend
\n" ); document.write( "------------------------------------------
\n" ); document.write( "Your friend's equation:
\n" ); document.write( "(1) $\"+d+=+12t+\"$
\n" ); document.write( "Your equation:
\n" ); document.write( "(2) $\"+d+%2B+3+=+18t+\"$
\n" ); document.write( "-----------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+12t+%2B+3+=+18t+\"$
\n" ); document.write( "(2) $\"+6t+=+3+\"$
\n" ); document.write( "(2) $\"+t+=+1%2F2+\"$
\n" ); document.write( "You catch your friend in a 1/2 hr
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+=+12%2A%281%2F2%29+\"$
\n" ); document.write( "(1) $\"+d+=+6+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+%2B+3+=+18%2A%281%2F2%29+\"$
\n" ); document.write( "(2) $\"+d+=+9+-+3+\"$
\n" ); document.write( "(2) $\"+d+=+6+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );