document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990952>Question 990952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 56 centimeters.  The longest side is 2 centimeters less than the sum of the other two sides.  Twice the shortest side is 13 centimeters less than the longest side.  Find the lengths of each side of the triangle.\r<BR>\n" );
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document.write( "a=<BR>\n" );
document.write( "b=<BR>\n" );
document.write( "c=a+b-2<BR>\n" );
document.write( "a+b+c=56 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610897 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c=longest side; a=shortest side; b=middle side<BR>\n" );
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document.write( "a+b=c+2 Use this to substitute for (a+b)<BR>\n" );
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document.write( "a+b+c=56 Substitute for (a+b)<BR>\n" );
document.write( "(c+2)+c=56<BR>\n" );
document.write( "2c=54<BR>\n" );
document.write( "c=27<BR>\n" );
document.write( "ANSWER 1: Longest side is 27 centimeters<BR>\n" );
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document.write( "c-13=2a<BR>\n" );
document.write( "27-13=2a<BR>\n" );
document.write( "14=2a<BR>\n" );
document.write( "7=a<BR>\n" );
document.write( "ANSWER 2: The shortest side is 7 centimeters<BR>\n" );
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document.write( "a+b+c=56<BR>\n" );
document.write( "7cm+b+27cm=56cm<BR>\n" );
document.write( "b+34cm=56cm<BR>\n" );
document.write( "b=22cm<BR>\n" );
document.write( "ANSWER 3: the middle side is 22 centimeters.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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