document.write( "Question 990904: Kiran drove from Tortula to Cactus, a distance of 212 mi. She increased her speed by 13 mi/h for the 385 mi trip from Cactus to Dry Junction. If the total trip took 10 h, what was her speed from Tortula to Cactus? \n" ); document.write( "
Algebra.Com's Answer #610896 by ankor@dixie-net.com(22740)\"\" \"About 
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Kiran drove from Tortula to Cactus, a distance of 212 mi.
\n" ); document.write( " She increased her speed by 13 mi/h for the 385 mi trip from Cactus to Dry Junction.
\n" ); document.write( " If the total trip took 10 h, what was her speed from Tortula to Cactus?
\n" ); document.write( ":
\n" ); document.write( "let s = speed from T to C
\n" ); document.write( "then
\n" ); document.write( "(s+13) = speed from C to D
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "\"212%2Fs\" + \"385%2F%28%28s%2B13%29%29\" = 10 hrs
\n" ); document.write( "multiply equation by s(s+13)
\n" ); document.write( "s(s+13)*\"212%2Fs\" + s(s+13)*\"385%2F%28%28s%2B13%29%29\" = 10s(s+13)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "212(s+13) + 385s = 10s^2 + 130s
\n" ); document.write( "212s + 2756 + 385s = 10s^2 + 130s
\n" ); document.write( "597s + 2756 = 10s^2 + 130s
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "10s^2 + 130s - 597s - 2756 = 0
\n" ); document.write( "10s^2 - 467s - 2756 = 0
\n" ); document.write( "Use the quadratic formula to find s: a=10; b=-467; c=-2756
\n" ); document.write( "I got a positive solution of 52 mph from T to C
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "you can check this for yourself
\n" ); document.write( "\"212%2F52\" + \"385%2F65\" =
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