document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990932>Question 990932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation for the line that passes through the point (-1,-3), and that is perpendicular to the line with the equation y=-1/3x+1.<BR>\n" );
document.write( "Slope: m1= -1/3<BR>\n" );
document.write( "Slope: m2= 3<BR>\n" );
document.write( "Y-(-3)= 3(x-(-1))<BR>\n" );
document.write( "3(y-(-3)) =3(x-(-1))<BR>\n" );
document.write( "3y-9= 3x-3<BR>\n" );
document.write( "3x-3y= 6<BR>\n" );
document.write( "Y= 3x+6<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610890 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm not sure why you did step 2. It is an incorrect algebraic move.\r<BR>\n" );
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document.write( "Here's how you do the problem\r<BR>\n" );
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document.write( "y-(-3)= 3(x-(-1)) ... you had step 1 correct<BR>\n" );
document.write( "y+3 = 3(x+1)<BR>\n" );
document.write( "y+3 = 3x+3<BR>\n" );
document.write( "y+3-3 = 3x+3-3 ... Subtract 3 from both sides.<BR>\n" );
document.write( "y = 3x\r<BR>\n" );
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document.write( "So the final answer is <font color=\"red\">y = 3x</font> </SPAN>\n" );
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