document.write( "Question 84734: A rectangualr garden measuring 8 m by 20 m has its area increased by 60 m^2 by the addition of a walk of uniform width around all sides. What is the width of the walk? \n" ); document.write( "
Algebra.Com's Answer #61088 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular garden measuring 8 m by 20 m has its area increased by 60 m^2 by the addition of a walk of uniform width around all sides. What is the width of the walk?
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\n" ); document.write( "Think of it this way.
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\n" ); document.write( "Let x = width of the path:
\n" ); document.write( "Total dimension = (2x+8) by (2x+20)
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\n" ); document.write( "Total area (including the garden & the walkway) - area of the garden = 60 sq/m
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\n" ); document.write( "[(2x+8)(2x+20)] - (8 * 20) = 60
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\n" ); document.write( "(4x^2 + 56x + 160) - 160 = 60
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\n" ); document.write( "4x^2 + 56x + 160 - 160 - 60 = 0
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\n" ); document.write( "4x^2 + 56x - 60 = 0
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\n" ); document.write( "Simplify, divide equation by 4:
\n" ); document.write( "x^2 + 14x - 15 = 0
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\n" ); document.write( "factors easily:
\n" ); document.write( "(x + 15)(x - 1) = 0
\n" ); document.write( "x = +1 ft is the width of the walkway (other solution would not make sense)
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\n" ); document.write( "Check solution of x = 1, Dimensions of the total area: (2+8)*(2+20)
\n" ); document.write( "10 * 22 = 220
\n" ); document.write( " 8 * 20 = 160
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\n" ); document.write( "differ = 60 sq/ft
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