document.write( "Question 990827: A fraction becomes 3/4 if 3 is added to both the numerator and denominator if 1 is subracted from the numerator and 1 is added to the denominator then it becomes 1/3 find the fraction \n" ); document.write( "

Algebra.Com's Answer #610869 by Timnewman(323) $\"\"$ $\"About$

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Hi dear,
\n" ); document.write( "the fraction is 3/5.
\n" ); document.write( "HERE IS THE WORKING:
\n" ); document.write( "Let the fraction be x/y
\n" ); document.write( "Then,from your first sentence,
\n" ); document.write( " $\"%28x%2B3%29%2F%28y%2B3%29=3%2F4\"$
\n" ); document.write( "4(x+3)=3(y+3)
\n" ); document.write( "4x+12=3y+9
\n" ); document.write( "4x-3y=-3----(1)
\n" ); document.write( "From your second sentence,
\n" ); document.write( " $\"%28x-1%29%2F%28y%2B1%29=1%2F3\"$
\n" ); document.write( "3(x-1)=y+1
\n" ); document.write( "3x-3=y+1
\n" ); document.write( "3x-y=4----(2)
\n" ); document.write( "Fro equ 2,
\n" ); document.write( "y=3x-4---(3)
\n" ); document.write( "put 3 in 1
\n" ); document.write( "4x-3(3x-4)=-3
\n" ); document.write( "4x-9x+12=-3
\n" ); document.write( "-5x=-15
\n" ); document.write( "x=3
\n" ); document.write( "put x=3 in equ 3
\n" ); document.write( "y=3(3)-4
\n" ); document.write( "y=9-4
\n" ); document.write( "y=5
\n" ); document.write( "Then,the fraction becomes 3/5
\n" ); document.write( "HOPE THIS HELPS?
\n" ); document.write( "::TIMNEWMAN:: \n" ); document.write( "

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