document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990833>Question 990833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been struggling with this word problem and I don't know where to start: What amount of a 50% acid solution must be mixed with a 25% solution to produce 500 mL of a 45% solution?<BR>\n" );
document.write( "If you could just help me get started that would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610811 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this one:<BR>\n" );
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document.write( "One alloy contains 80% gold (by weight)and another alloy contains 55% gold.how many grams of each alloy should be combined to make 40g of an alloy that contains 70% gold.<BR>\n" );
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document.write( "e = amount of 80%<BR>\n" );
document.write( "f = amount of 55%<BR>\n" );
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document.write( "e + f = 40  (total alloy)<BR>\n" );
document.write( "80e + 55f = 70*40 (total gold)<BR>\n" );
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