document.write( "Question 990789: how many different product of 3 digits can be formed from the digits 2,5 and 7 without repetition ? \n" ); document.write( "
Algebra.Com's Answer #610792 by Edwin McCravy(20055)\"\" \"About 
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document.write( "How many different products of 3 digits??\r\n" );
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document.write( "Only one product of the three digits 2,5, and 7 is possible, that is:\r\n" );
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document.write( "2x5x7 = 2x7x5 = 5x2x7 = 5x7x2 - 7x2x5 = 7x5x2 = 70.\r\n" );
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document.write( "Maybe you didn't know that \"product\" means \"what you get when you multiply\".\r\n" );
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document.write( "Maybe you didn't want any product at all.\r\n" );
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document.write( "Maybe you just wanted to know how many ways 2, 5, and 7 can be rearranged.\r\n" );
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document.write( "That would be 6 ways: 257, 275, 527, 572, 725, 752.\r\n" );
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document.write( "Or, maybe you wanted this kind of a product:\r\n" );
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document.write( "3 ways to choose the first digit\r\n" );
document.write( "times\r\n" );
document.write( "2 ways remaining to chose for the second digit, and\r\n" );
document.write( "times\r\n" );
document.write( "1 way remaining to choose the third digit.\r\n" );
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document.write( "Which is \r\n" );
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document.write( "3x2x1 or 3! or 3P3 or \"number of permutations of 3 things taken 3 at a time\"\r\n" );
document.write( "or 6.\r\n" );
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document.write( "Edwin
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