document.write( "Question 990735: I'm having a difficult time figuring out how to set up my equations in order to solve using a system of equations. The problem:\r
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document.write( "In winning the Western Conference finals, the San Antonia Spurs once scored 76 of their points on a combination of 36 two- and three- pointers. How many shots of each type did they make? \r
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document.write( "I initially set it up as:\r
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document.write( "x + y = 76,
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document.write( "3x + 2y = 36, \r
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document.write( "but that clearly didn't work out. I appreciate the help. Thank you! \n" );
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Algebra.Com's Answer #610733 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 3x + 2y = 76, where x is number of 3 point shots and y is number of 2 point shots \n" ); document.write( "x + y = 36 \n" ); document.write( "solve for x and substitute in first equation \n" ); document.write( "x = 36 - y \n" ); document.write( "3(36 - y) + 2y = 76 \n" ); document.write( "108 -3y + 2y = 76 \n" ); document.write( "-y = -32 \n" ); document.write( "y = 32 \n" ); document.write( "x + 32 = 36 \n" ); document.write( "x = 4, therefore \n" ); document.write( "there were 32 2-point shots and 4 3-point shots \n" ); document.write( "************************************************ \n" ); document.write( "check the answer \n" ); document.write( "3(4) + 2(32) = 76 \n" ); document.write( "12 + 64 = 76 \n" ); document.write( "76 = 76 \n" ); document.write( "our answer checks\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |