document.write( "Question 990655: If X+y+z=112 and y=4x and z=11y then find the value of y \n" ); document.write( "

Algebra.Com's Answer #610687 by ikleyn(52798) $\"\"$ $\"About$

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\n" ); document.write( "You are given\r
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\n" ); document.write( "\n" ); document.write( "x + y + z = 112,\r
\n" ); document.write( "\n" ); document.write( "y = 4x,\r
\n" ); document.write( "\n" ); document.write( "z = 11y.\r
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\n" ); document.write( "\n" ); document.write( "Find y.
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\n" ); document.write( "\n" ); document.write( "Substitute y = 4x and z = 11y = 11*(4x) = 44x into the first equation. You will have \r
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\n" ); document.write( "\n" ); document.write( "x + 4x + 44x = 112, or\r
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\n" ); document.write( "\n" ); document.write( "49x = 112.\r
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\n" ); document.write( "\n" ); document.write( "Hence, x = $\"112%2F49\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Therefore, y = 4x = $\"%284%2A112%29%2F49\"$ = $\"448%2F49\"$ .\r
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