document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990684>Question 990684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man, that day will be the date as the money is used to spending.<BR>\n" );
document.write( "(Eg. 18 to Rs 18 on.) Once the 5 consecutive days was spent Rs 63, but which was 5 days (say dates) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610675 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52852)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Let me re-formulate the problem in more clear way:\r<BR>\n" );
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document.write( "Mr. Z had a habit of spending money according to dates. i. e. If date is 19 he was spending Rs.19 and if date is 15, he was spending Rs. 15. <BR>\n" );
document.write( "One night he calculated total spending of 5 consecutive days, and he found that he spent Rs. 63 in 5 days. <BR>\n" );
document.write( "So, identify the dates.\r<BR>\n" );
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document.write( "<B>Answer</B>. &nbsp;There is only one solution:\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;28 and 29 &nbsp;of February &nbsp;(a leap-year)&nbsp; and &nbsp;1, 2, &nbsp;and &nbsp;3 &nbsp;of March.\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(28 + 29 + 1 + 2 + 3 = 63). \r<BR>\n" );
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document.write( "<B>Solution</B>\r<BR>\n" );
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document.write( "If these days would be inside one month, &nbsp;then the dates are &nbsp;(x-2), &nbsp;(x-1), &nbsp;x, &nbsp;(x+1) &nbsp;and &nbsp;(x+2), &nbsp;where x is the date of the middle of &nbsp;5 days. \r<BR>\n" );
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document.write( "Then the sum must be multiple of &nbsp;5, &nbsp;since \r<BR>\n" );
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document.write( "(x-2) + (x-1) + x + (x+1) + (x+2) = 5x.\r<BR>\n" );
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document.write( "But the integer &nbsp;63&nbsp; is not multiple of &nbsp;5. &nbsp;Contradiction. \r<BR>\n" );
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document.write( "Hence, &nbsp;the dates are partly the end of some month and the beginning of the next month. \r<BR>\n" );
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document.write( "Then, &nbsp;it is easy to check the the dates &nbsp;28, &nbsp;29, &nbsp;1, &nbsp;2 &nbsp;and 3 &nbsp;satisfy the condition &nbsp;28 + 29 + 1 + 2 + 3 = 63. \r<BR>\n" );
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document.write( "Next, &nbsp;it is easy to see that there is no other solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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