document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990614>Question 990614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of a brother and sister is 28. if four time the brothers age is subtracted from three times the sister age , the difference is 14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610654 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of the brother and sister be x and y.<BR>\n" );
document.write( "from your question,<BR>\n" );
document.write( "x+y=28----(1)<BR>\n" );
document.write( "3x-4y=14----(2)<BR>\n" );
document.write( "from 1,<BR>\n" );
document.write( "x=28-y---(3)<BR>\n" );
document.write( "put 3 in 2<BR>\n" );
document.write( "3(28-y)-4y=14<BR>\n" );
document.write( "84-3y-4y=14<BR>\n" );
document.write( "7y=70<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "put y=10 in 3<BR>\n" );
document.write( "x=28-10<BR>\n" );
document.write( "x=18<BR>\n" );
document.write( "The ages of sister and brother is 18yrs and 10yrs respectively.<BR>\n" );
document.write( "HOPE THIS HELPS? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );