document.write( "Question 990608: A rectangle has a length that is 3 feet more than the width. If the area of the rectangle is 52 square feet more than the area of a square with side 6, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #610624 by josgarithmetic(39617)\"\" \"About 
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Length L, width w;
\n" ); document.write( "\"system%28L=w%2B3%2CwL=52-6%2A6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w%28w%2B3%29=52-36\"
\n" ); document.write( "\"w%5E2-3w=56-40=16\"
\n" ); document.write( "\"w%5E2-3w-16=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"w=%283%2Bsqrt%289%2B4%2A16%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28w=%283%2Bsqrt%2873%29%29%2F2%29\"
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