document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990600>Question 990600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of a circle has endpoints J(12,25) and K(-10,13). Find the circumstance and area the circle. Use the pie key on your calculator and round to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610612 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi dear,<BR>\n" );
document.write( "Use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Where y1=25,y2=13,x1=12,x2=-10<BR>\n" );
document.write( "put the above in the formula and get diameter of the circle to be 25.01<BR>\n" );
document.write( "Now radius r=25.01/2<BR>\n" );
document.write( "=12.51<BR>\n" );
document.write( "circumference=2*pi*12.51<BR>\n" );
document.write( "=78.61<BR>\n" );
document.write( "area=pi*12.51²<BR>\n" );
document.write( "=941.72 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );