document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990550>Question 990550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that the sides of an equilateral triangle is 4a+6,3b-2a,and 2b+2 respectively find a and b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610595 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since it is an equilateral triangle,<BR>\n" );
document.write( "Then,<BR>\n" );
document.write( "4a+6=3b-2a<BR>\n" );
document.write( "4a+2a-3b=-6<BR>\n" );
document.write( "6a-3b=-6-----(1)<BR>\n" );
document.write( "Divide throught by 3<BR>\n" );
document.write( "2a-b=-2-----(2)<BR>\n" );
document.write( "also,<BR>\n" );
document.write( "3b-2a=2b+2<BR>\n" );
document.write( "3b-2b-2a=2<BR>\n" );
document.write( "b-2a=2------(3)<BR>\n" );
document.write( "from equ 3<BR>\n" );
document.write( "b=2a+2----(4)<BR>\n" );
document.write( "put 4 in 2<BR>\n" );
document.write( "3a-(2a+2)=-2<BR>\n" );
document.write( "3a-2a-2=-2<BR>\n" );
document.write( "a=-2+2<BR>\n" );
document.write( "a=0<BR>\n" );
document.write( "put a=0 in equ 4<BR>\n" );
document.write( "b=2(0)-2<BR>\n" );
document.write( "b=0-2<BR>\n" );
document.write( "b=-2<BR>\n" );
document.write( "The value of a and b are 0 and -2 respectively.<BR>\n" );
document.write( "HOPE THIS HELPS? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );