document.write( "Question 84766This question is from textbook finite mathmatics
\n" ); document.write( ": When the constraint 6x1 + 17x2 < 28 is converted to an equation, the equation is\r
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\n" ); document.write( "\n" ); document.write( "A. 6x1 + 17x2 = 28
\n" ); document.write( "B. 6x1 + 17x2 - 28 = 0
\n" ); document.write( "C. 6x1 + 17x2 + s1 = 28
\n" ); document.write( "D. 6x1 + 17x2 - s1 = 28
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Algebra.Com's Answer #61057 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "When the constraint 6x1 + 17x2 < 28 \r\n" );
document.write( "is converted to an equation, the equation is\r\n" );
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document.write( "A. 6x1 + 17x2 = 28\r\n" );
document.write( "B. 6x1 + 17x2 - 28 = 0\r\n" );
document.write( "C. 6x1 + 17x2 + s1 = 28\r\n" );
document.write( "D. 6x1 + 17x2 - s1 = 28\r\n" );
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document.write( "6x1 + 17x2 < 28\r\n" );
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document.write( "When the left side is less than the right side 28, then\r\n" );
document.write( "a positive number must be added to the left side to \"take\r\n" );
document.write( "up the slack\" between the smaller left side and the larger\r\n" );
document.write( "right side.  So we add a \"slack variable\" s1 to\r\n" );
document.write( "the left side as the proper positive number that will\r\n" );
document.write( "\"take up the slack\" between the smaller left side and the \r\n" );
document.write( "larger right side.  [No harm is done when the left side \r\n" );
document.write( "exactly equals the right side because in that case s1 \r\n" );
document.write( "just becomes 0].  So the only choice which adds s1\r\n" );
document.write( "to the left side is choice C.\r\n" );
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document.write( "Edwin
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