document.write( "Question 990521: The average age of father and his son is 54 years and after 10 years the ratio of their ages will be
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document.write( "3 : 1. So find the present age of father.
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document.write( "(1) 82 years (2) 84 years (3) 86 years (4) 89 years \n" );
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Algebra.Com's Answer #610551 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=father's age; S=son's age \n" ); document.write( ". \n" ); document.write( "(F+S)/2=54yrs \n" ); document.write( "F+S=108yrs \n" ); document.write( "S=108yrs-F \n" ); document.write( ". \n" ); document.write( "F+10yrs=3(S+10yrs) \n" ); document.write( "F+10yrs=3(108yrs-F+10yrs) \n" ); document.write( "F+10yrs=3(118yrs-F) \n" ); document.write( "F+10yrs=354yrs-3F \n" ); document.write( "4F=344yrs \n" ); document.write( "F=86yrs \n" ); document.write( "ANSWER: Father's present age is (c) 86 years. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "S=108yrs-86yrs=22yrs \n" ); document.write( "Son's age is 22 years. \n" ); document.write( ". \n" ); document.write( "F+10yrs=3(S+10yrs) \n" ); document.write( "86yrs+10yrs=3(22yrs+10yrs) \n" ); document.write( "96yrs=3(32yrs) \n" ); document.write( "96yrs=96yrs\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |