document.write( "Question 990543: 23% solution is added to 17% solution to get 45 gallons of 20% solution. How much of each should be added? \n" ); document.write( "

Algebra.Com's Answer #610540 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "T=amount of 23% solution; S=amount of 17% solution
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\n" ); document.write( "T+S=45 gallons
\n" ); document.write( "S=45 gallons-T
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\n" ); document.write( "0.23T+0.17S=0.20(45 gallons)
\n" ); document.write( "0.23T+0.17(45gal-T)=9gal
\n" ); document.write( "0.23T+7.65gal-0.17T=9gal
\n" ); document.write( "0.06T=1.35gal
\n" ); document.write( "T=22.5 gallons
\n" ); document.write( "ANSWER 1: 22.5 gallons of 23% solution should be added.
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\n" ); document.write( "S=45gal-T=45gal-22.5gal=22.5gal
\n" ); document.write( "ANSWER 2: 22.5 gallons of 17% solution should be added.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "0.23T+0.17S=0.20(45 gallons)
\n" ); document.write( "0.23(22.5gal)+0.17(22.5gal)=0.20(45gal)
\n" ); document.write( "5.175gal+3.825gal=9gal
\n" ); document.write( "9gal=9gal\r
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