document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990540>Question 990540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please last i as this question but there was no response am asing it again<BR>\n" );
document.write( "13log(25/4)-2log(4/5)+log(320/125) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610538 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13log(25/4)-2log(4/5)+log(320/125)=<BR>\n" );
document.write( "13 log 25-13 log 4-2 log 4+2 log 5+log 320-log 125=<BR>\n" );
document.write( "13 log 25-log 125-15 log 4+2 log 5+ log 320.;;- a log with a denominator will be + for the denominator<BR>\n" );
document.write( "13log 25-log 5^3-15 log 4+2 log 5+log (5*l64)<BR>\n" );
document.write( "13 log 5^2-3 log 5-15 log 4+2 log 5+log 5+log 64<BR>\n" );
document.write( "26 log 5-3 log 5-15 log 4 + 3 log 5+ log 4^3<BR>\n" );
document.write( "23 log 5-15 log 4+3 log 5+3 log 4<BR>\n" );
document.write( "26 log 5-12 log 4<BR>\n" );
document.write( "also 26 log 5-12 log 2^2=26 log 5-24 log 2.<BR>\n" );
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document.write( "check numerically 18.17-7.22=10.95<BR>\n" );
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document.write( "13 log 6.25=10.35<BR>\n" );
document.write( "-2 log (0.8)=+0.19<BR>\n" );
document.write( "+log(320/125)=0.41<BR>\n" );
document.write( "These add to 10.95<BR>\n" );
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