document.write( "Question 990525: Find three consecutive numbers whose sum is 99.
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Algebra.Com's Answer #610532 by farohw(175)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x + (x + 1) + (x + 2) = 99 --> x + x + 1 + x + 2 = 99\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Adding will yield, 3x + 3 = 99 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 3 = 99 --> 3x = 99 - 3 --> 3x = 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x/3 = 96/3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 32 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 3 consecutive numbers are 32, 33, 34.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Verify:\r \n" ); document.write( "\n" ); document.write( "32 + 33 + 34 = 99\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |