document.write( "Question 84750: I WOULD LIKE SOME HELP ON THE FOLLOWING QUESTION PLEASE.\r
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\n" ); document.write( "\n" ); document.write( "36hk^3, 60k^2m, 84k^4n \n" ); document.write( "
Algebra.Com's Answer #61053 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I WOULD LIKE SOME HELP ON THE FOLLOWING QUESTION PLEASE. \r\n" );
document.write( "Find the GCF. \r\n" );
document.write( "36hk^3, 60k^2m, 84k^4n\r\n" );
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document.write( "Break everything down into prime factors\r\n" );
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document.write( "36hk3 = 2·2·3·3·k·k·k\r\n" );
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document.write( "60k2m = 2·2·3·5·k·k·m\r\n" );
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document.write( "84k4n = 2·2·3·7·k·k·k·k·n\r\n" );
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document.write( "I notice that the first three factors 2·2·3 are common to \r\n" );
document.write( "all three expressions, so I will color them red.  You can \r\n" );
document.write( "just circle them on your paper:\r\n" );
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document.write( "36hk3 = 2·2·3·3·k·k·k\r\n" );
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document.write( "60k2m = 2·2·3·5·k·k·m\r\n" );
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document.write( "84k4n = 2·2·3·7·k·k·k·k·n\r\n" );
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document.write( "I can't color the remaining 3, the 5 or the 7 red because these \r\n" );
document.write( "are not common to all three expressions.  However, the first two \r\n" );
document.write( "k's are common to all three, so I can color them red: \r\n" );
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document.write( "36hk3 = 2·2·3·3·k·k·k\r\n" );
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document.write( "60k2m = 2·2·3·5·k·k·m\r\n" );
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document.write( "84k4n = 2·2·3·7·k·k·k·k·n\r\n" );
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document.write( "I can't color any of the remaining k's in the first and third \r\n" );
document.write( "expressions red because they are not contained in the second.\r\n" );
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document.write( "So the GCF consists only of the red (or your circled) factors, so\r\n" );
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document.write( "GCF = 2·2·3·k·k \r\n" );
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document.write( "Then multiply those together as\r\n" );
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document.write( "GCF = 12k2\r\n" );
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document.write( "If you do enough of these, you will learn to shorten this\r\n" );
document.write( "process by doing some of it in your head.  You will also\r\n" );
document.write( "notice that you will use the smallest exponent of any\r\n" );
document.write( "letter that appears in all expressions.  But to get the\r\n" );
document.write( "hang of GCF, do it this longer way for awhile.\r\n" );
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document.write( "Edwin
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