document.write( "Question 990397: Two printers are put to work printing 200 copies of a document. One of the printers takes 2.5 minutes to print a copy; the other will print a copy in 1.5 minutes.
\n" ); document.write( "a. Let x represent the time in mintes that both copiers work to complete the job. Write an exoression for how many copies both printers will print in x amount of minutes.
\n" ); document.write( "b. How long will it take both printers working together to complete the job?
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Algebra.Com's Answer #610489 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "printers       copies   time    rate\r\n" );
document.write( "printer         1        2.5    1/2.5\r\n" );
document.write( "printer         1        1.5    1/1.5\r\n" );
document.write( "both at once    1        x      1/x\r\n" );
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\n" ); document.write( "\n" ); document.write( "All rates are using 1 copy but different time amounts. The x is for time in minutes for 1 copy; and the individual rates are additive to make the combined rate.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F2.5%2B1%2F1.5=1%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%285%2F2%29%2B1%2F%283%2F2%29=1%2Fx\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2F5%2B2%2F3=1%2Fx\"
\n" ); document.write( "Simplest common denominator, 15x.
\n" ); document.write( "\"%282%2F5%2B2%2F3%29%2815x%29=15\"
\n" ); document.write( "\"6x%2B10x=15\"
\n" ); document.write( "\"16x=15\"
\n" ); document.write( "\"highlight%28x=15%2F16%29\"---------THIS is how many minutes for the two printers together to make 1 copy; *but in practice, nobody uses more than one printer to make just one copy. This is really 16 copies per each 15 minutes.
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