document.write( "Question 84758: Steve traveled 600 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.\r
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Algebra.Com's Answer #61046 by pg2000in(2)\"\" \"About 
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We know that distance = speed * time. Now Let us denote the speed by s and speed by t then
\n" ); document.write( "600= s * t
\n" ); document.write( "where s is in miles per hour and t is in hours
\n" ); document.write( "Now Second condition says that had he gone 20mph faster, the trip would have taken 1 hour less. But the distance remains the same
\n" ); document.write( "so
\n" ); document.write( "in the second case:
\n" ); document.write( "600=(s+20)(t-1)
\n" ); document.write( "which means if we equate the two equations, we have\r
\n" ); document.write( "\n" ); document.write( "st= (s+20)(t-1)
\n" ); document.write( "solving:
\n" ); document.write( "s= 20t -20\r
\n" ); document.write( "\n" ); document.write( "substituting the value of t from the equation 600 = st in terms of s, we have
\n" ); document.write( "\"s=+%28%2820%2A600%29%2Fs%29-20\"
\n" ); document.write( "which yields to
\n" ); document.write( "\"s%5E2%2B20%2As-12000=0\"
\n" ); document.write( "solving by quadratic equation method and taking the positive value only, we have
\n" ); document.write( "s=100 miles per hour\r
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