document.write( "Question 84758: Steve traveled 600 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.\r
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Algebra.Com's Answer #61046 by pg2000in(2)![]() ![]() ![]() You can put this solution on YOUR website! We know that distance = speed * time. Now Let us denote the speed by s and speed by t then \n" ); document.write( "600= s * t \n" ); document.write( "where s is in miles per hour and t is in hours \n" ); document.write( "Now Second condition says that had he gone 20mph faster, the trip would have taken 1 hour less. But the distance remains the same \n" ); document.write( "so \n" ); document.write( "in the second case: \n" ); document.write( "600=(s+20)(t-1) \n" ); document.write( "which means if we equate the two equations, we have\r \n" ); document.write( "\n" ); document.write( "st= (s+20)(t-1) \n" ); document.write( "solving: \n" ); document.write( "s= 20t -20\r \n" ); document.write( "\n" ); document.write( "substituting the value of t from the equation 600 = st in terms of s, we have \n" ); document.write( " \n" ); document.write( "which yields to \n" ); document.write( " \n" ); document.write( "solving by quadratic equation method and taking the positive value only, we have \n" ); document.write( "s=100 miles per hour\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |