document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990408>Question 990408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This problem I and having major difficulty with. Could someone explain this in a simple way. My teacher made it very difficult and didn't clear up many of my fellow students questions. \r<BR>\n" );
document.write( "\n" );
document.write( "Q: The distance of an object above the ground at time t is given by h(t) = cos(t). What is the velocity v(pi/3) of the object at t =pi/3. \r<BR>\n" );
document.write( "\n" );
document.write( "Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610444 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first derivative gives us the velocity, therefore<BR>\n" );
document.write( "h'(t) = -sin(t)<BR>\n" );
document.write( "now t=pi/3 is in radians<BR>\n" );
document.write( "h'(t) = -sin(pi/3) = 0.304810621 downwards </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );