document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990433>Question 990433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A carpenter has three pieces of wood measuring 210cm,245cm, and 315'cm in lenght. She wants to cut them into shorter pieces that are all the same length and with no wood left over. what is the greatest possible lenght of each shorted piece? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610432 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A carpenter has three pieces of wood measuring 210cm,245cm, and 315'cm in lenght. She wants to cut them into shorter pieces that are all the same length and with no wood left over. what is the greatest possible length of each shorted piece? <BR>\n" );
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document.write( "210 = 2*105 = 2*5*21 = 2*3*5*7<BR>\n" );
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document.write( "245 = 5*49 = 5*7^2<BR>\n" );
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document.write( "315 = 5*63 = 3^2 * 5* 7<BR>\n" );
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document.write( "Greatest common Divisor:: 5*7 = 35<BR>\n" );
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document.write( "210 = 35*6:: 6 pieces of size 35<BR>\n" );
document.write( "245 = 35*7:: 7 pieces of size 35<BR>\n" );
document.write( "315 = 35*9:: 9 pieces of size 35<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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