document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990414>Question 990414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 79 . the second number is 5 times the first , while the third is 15 more than the first . find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610417 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number; S=second number=5F; T=third number=F+15<BR>\n" );
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document.write( "F+S+T=79<BR>\n" );
document.write( "F+(5F)+(F+15)=79<BR>\n" );
document.write( "7F+15=79<BR>\n" );
document.write( "7F=64<BR>\n" );
document.write( "F=64/7<BR>\n" );
document.write( "S=5(F)=5(64/7)=320/7<BR>\n" );
document.write( "T=F+15=64/7+105/7=169/7<BR>\n" );
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document.write( "ANSWER: The numbers are 64/7, 320/7, and 169/7.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
document.write( "(64/7)+(320/7)+(169/7)=79<BR>\n" );
document.write( "553/7=79<BR>\n" );
document.write( "79=79 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );