document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148291>Question 148291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ways can a baseball coach choose the first, second and third batters in the lineup of a team of 15 players. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610411 by </B><A HREF=/tutors/aboutme.mpl?userid=alnavy70><B>alnavy70(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alnavy70><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this particular question, the different ways of possible players that a coach can choose from the 1st, 2nd, and 3rd batter. Therefore, using The Rule of Sum we can solve. \r<BR>\n" );
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document.write( "For the 1st player he has 15 different ways to choose from<BR>\n" );
document.write( "For the 2nd player he has 14 different ways to choose from<BR>\n" );
document.write( "For the 3rd player he has 13 different ways to choose from\r<BR>\n" );
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document.write( "Therefore, \r<BR>\n" );
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document.write( "For the first experiment or the second or the last is 15 + 14 + 13 = 42 possible ways the coach can choose the 1st, 2nd, and 3rd batters.  </SPAN>\n" );
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