document.write( "Question 990349: 6a+3b=4,a+b=1 \n" ); document.write( "

Algebra.Com's Answer #610374 by Boreal(15235) $\"\"$ $\"About$

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6a+3b=4
\n" ); document.write( "a+b=1
\n" ); document.write( "b=1-a
\n" ); document.write( "substitute into first equation
\n" ); document.write( "6a+3(1-a)=4
\n" ); document.write( "6a+3-3a=4
\n" ); document.write( "3a=1
\n" ); document.write( "a=(1/3)
\n" ); document.write( "b=(2/3)
\n" ); document.write( "6*(1/3)=2
\n" ); document.write( "3*(2/3)=2
\n" ); document.write( "and 6a+3b=4
\n" ); document.write( " \n" ); document.write( "

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