document.write( "Question 990242: Find the value of x that minimises \r
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document.write( "y = 16x^2 + 1800/x\r
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document.write( "for positive x. \r
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document.write( "So first I need to differentiate, which would give y' = 32x - 1800/x^2\r
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document.write( "I am stuck with the next 4 parts..\r
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document.write( "How many critical numbers does y have, for positive x?
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document.write( "Recall that a critical number of a function is a value of x for which the derivative of the function is zero or doesn't exist.\r
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document.write( "What is the nature of the critical number of the previous part?
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document.write( "Enter m for minimum, M for maximum or i for a horizontal point of inflection.\r
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document.write( "Give the exact value of the x that minimises y for positive x.
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document.write( "x (at minimum) =\r
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document.write( "Now give the value approximately as a 2 decimal place decimal. Now, give the approximate value (as a 2 decimal place decimal) of the x that minimises y for positive x.
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document.write( "x (at minimum) ≈\r
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document.write( "THANK YOU \n" );
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Algebra.Com's Answer #610282 by josgarithmetic(39631) ![]() You can put this solution on YOUR website! Where is the derivative equal to zero? \n" ); document.write( "Simplify that derivative and then solve this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The factor of 8 can probably not be needed because you are looking for the NUMERATOR to be zero; and for the same reason, the x in the numerator is not important for this. \n" ); document.write( "You now just need to solve for |