document.write( "Question 84576: Solve. We are working with Quadratic Equations and Functions\r
\n" ); document.write( "\n" ); document.write( "You have 188 ft of fencing to enclose a rectangular region. What is the maximum area?
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Algebra.Com's Answer #61028 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve. We are working with Quadratic Equations and Functions:
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\n" ); document.write( "You have 188 ft of fencing to enclose a rectangular region. What is the maximum area?
\n" ); document.write( "Perimeter:
\n" ); document.write( "2L + 2W = 188
\n" ); document.write( "Simplify, divide equation by 2:
\n" ); document.write( "L + W = 94
\n" ); document.write( "W = 94 - L
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\n" ); document.write( "Let x = length
\n" ); document.write( "Then:
\n" ); document.write( "(94-x) = width
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\n" ); document.write( "The area = y:
\n" ); document.write( "y = x(94-x)
\n" ); document.write( "y = -x^2 + 94x; a quadratic equation:
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\n" ); document.write( "Find the axis of symmetry: x = -b/(2a)
\n" ); document.write( "In our equation: a = -1; b = +94
\n" ); document.write( "x = -94/(2*-1)
\n" ); document.write( "x = -94/-2
\n" ); document.write( "x = +47 the axis of symmetry
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\n" ); document.write( "Substitute 47 for x in the equation to find the vertex (max)
\n" ); document.write( "y = -(47^2) + 94(47)
\n" ); document.write( "y = -2209 + 4418
\n" ); document.write( "y = +2209 sq/ft max area with 188 ft perimeter\r
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