document.write( "Question 990108: Paul bikes for 3 hours to reach his favorite beach. He bikes 2 miles per hour faster on the way back. So the trip takes only 2.5 hours. How fast did he bike going to the beach? \n" ); document.write( "
Algebra.Com's Answer #610253 by ankor@dixie-net.com(22740)\"\" \"About 
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Paul bikes for 3 hours to reach his favorite beach.
\n" ); document.write( " He bikes 2 miles per hour faster on the way back.
\n" ); document.write( " So the trip takes only 2.5 hours.
\n" ); document.write( " How fast did he bike going to the beach?
\n" ); document.write( ":
\n" ); document.write( "let s = the slower speed
\n" ); document.write( "then
\n" ); document.write( "(s+2) = the faster speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, the dist there and back are the same therefore
\n" ); document.write( "3s = 2.5(s+2)
\n" ); document.write( "3s = 2.5s + 5
\n" ); document.write( "3s - 2.5s = 5
\n" ); document.write( ".5s = 5
\n" ); document.write( "s = 5/.5
\n" ); document.write( "s = 10 mph to the beach
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual distance each way, should be the same
\n" ); document.write( "3*10 = 30 mi
\n" ); document.write( "2.5(12) = 30 mi \n" ); document.write( "
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