document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=990060>Question 990060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7, 16, 8, 27, 9, ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #610174 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=610174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "7, 16, 8, 27, 9, (40), (10)...\r<BR>\n" );
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document.write( "It appears that every other number starting at 7 is consecutive. Hence, 7, 8, 9, 10. However 16, 27, 40 are multiplied by 2*8 = 16, 3*9 = 27 and 4*10 = 40. Many times these things are solved through trial and error, sometimes you have to work backwards so to speak but do you see the pattern?\r<BR>\n" );
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document.write( "Best,\r<BR>\n" );
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document.write( "Farohw\r<BR>\n" );
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